$$\frac{3}{\pi} (arcsin(-\frac{\sqrt{3}}{2}) + arctg 1)$$
$$arcsin(-\frac{\sqrt{3}}{2}) = -\frac{\pi}{3}$$
$$arctg 1 = \frac{\pi}{4}$$
$$\frac{3}{\pi} (-\frac{\pi}{3} + \frac{\pi}{4}) = \frac{3}{\pi} (\frac{-\pi}{12}) = -\frac{3\pi}{12\pi} = -\frac{1}{4}$$
Ответ: -$$\frac{1}{4}$$