2) $$(3x-2)^2 + (1-2x)(3x+2) = 36$$

Решение: $$(3x-2)^2 + (1-2x)(3x+2) = 36$$. Раскрываем скобки: $$(9x^2 - 12x + 4) + (3x + 2 - 6x^2 - 4x) = 36$$. Упрощаем: $$9x^2 - 12x + 4 + 3x + 2 - 6x^2 - 4x = 36$$. $$3x^2 - 13x + 6 = 36$$. $$3x^2 - 13x - 30 = 0$$. $$D = (-13)^2 - 4*3*(-30) = 169 + 360 = 529$$. $$x_1 = \frac{13 + \sqrt{529}}{6} = \frac{13 + 23}{6} = \frac{36}{6} = 6$$. $$x_2 = \frac{13 - \sqrt{529}}{6} = \frac{13 - 23}{6} = \frac{-10}{6} = -\frac{5}{3}$$. Ответ: 6; -$$\frac{5}{3}$$