Преобразуем уравнение:
$$ 9 - 7x - 13x^2 = -7x - 10x^2 - 4 $$
$$ -3x^2 = -13 $$
$$ x^2 = \frac{13}{3} $$
$$ x_1 = \sqrt{\frac{13}{3}} = \frac{\sqrt{39}}{3} $$
$$ x_2 = -\sqrt{\frac{13}{3}} = -\frac{\sqrt{39}}{3} $$
Ответ: $$ x_1 = \frac{\sqrt{39}}{3}, x_2 = -\frac{\sqrt{39}}{3} $$