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МатематикаВопрос:
18) [3$$\frac{1}{4} \cdot (14$$\frac{4}{5}$$+$$\frac{4}{15}$$)-47]:5$$\frac{9}{10}$$
Ответ:
18) [3$$\frac{1}{4} \cdot (14$$\frac{4}{5}$$+$$\frac{4}{15}$$)-47]:5$$\frac{9}{10}$$ = [$$\frac{13}{4} \cdot (\frac{74}{5} + \frac{4}{15}$$) - 47] : $$\frac{59}{10}$$ = [$$\frac{13}{4} \cdot (\frac{222 + 4}{15}$$) - 47] : $$\frac{59}{10}$$ = [$$\frac{13}{4} \cdot \frac{226}{15}$$ - 47] : $$\frac{59}{10}$$ = [$$\frac{13 \cdot 113}{2 \cdot 15}$$ - 47] : $$\frac{59}{10}$$ = [$$\frac{1469}{30}$$ - $$\frac{1410}{30}$$] : $$\frac{59}{10}$$ = $$\frac{59}{30}$$ : $$\frac{59}{10}$$ = $$\frac{1}{3}$$
Ответ: $$\frac{1}{3}$$
Похожие
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