14) $$\frac{7\frac{1}{2} \cdot 2\frac{2}{3}-12\frac{1}{4}:\frac{7}{2}}{110:\frac{3}{5}+\frac{3\frac{3}{8}+2\frac{3}{4}}{24:2\frac{2}{5}}}$$ = $$\frac{\frac{15}{2} \cdot \frac{8}{3} - \frac{49}{4} : \frac{7}{2}}{110 \cdot \frac{5}{3} + \frac{\frac{27}{8} + \frac{11}{4}}{24 : \frac{12}{5}}}$$ = $$\frac{20 - \frac{49 \cdot 2}{4 \cdot 7}}{\frac{550}{3} + \frac{\frac{27 + 22}{8}}{24 \cdot \frac{5}{12}}}$$ = $$\frac{20 - \frac{7}{2}}{\frac{550}{3} + \frac{\frac{49}{8}}{10}}$$ = $$\frac{\frac{40 - 7}{2}}{\frac{550}{3} + \frac{49}{80}}$$ = $$\frac{\frac{33}{2}}{\frac{44000 + 147}{240}}$$ = $$\frac{\frac{33}{2}}{\frac{44147}{240}}$$ = $$\frac{33 \cdot 240}{2 \cdot 44147}$$ = $$\frac{3960}{44147}$$
Ответ: $$\frac{3960}{44147}$$