\(6 \frac{sin(α + β)-sinβcosα}{sin(α - β)+sinβcosα} = 1\); \(7 \frac{\sqrt{2} cosα-2sin(45°-α)}{2sin(60°+α)-\sqrt{3} cosα} = \sqrt{2}\)

6) \(\frac{sin(α + β)-sinβcosα}{sin(α - β)+sinβcosα} = \frac{sinαcosβ+cosαsinβ-sinβcosα}{sinαcosβ-cosαsinβ+sinβcosα} = \frac{sinαcosβ}{sinαcosβ} = 1\) 7) \(\frac{\sqrt{2} cosα-2sin(45°-α)}{2sin(60°+α)-\sqrt{3} cosα} = \frac{\sqrt{2} cosα-2(sin45°cosα - cos45°sinα)}{2(sin60°cosα+cos60°sinα)-\sqrt{3} cosα} = \frac{\sqrt{2} cosα-2(\frac{\sqrt{2}}{2}cosα - \frac{\sqrt{2}}{2}sinα)}{2(\frac{\sqrt{3}}{2}cosα + \frac{1}{2}sinα)-\sqrt{3} cosα} = \frac{\sqrt{2} cosα - \sqrt{2} cosα + \sqrt{2} sinα}{\sqrt{3} cosα + sinα - \sqrt{3} cosα} = \frac{\sqrt{2} sinα}{sinα} = \sqrt{2}\)