$$(\frac{1}{3})^9 : (\frac{1}{3})^2 : (\frac{1}{3})^3 = (\frac{1}{3})^{9-2-3} = (\frac{1}{3})^{9-5} = (\frac{1}{3})^4 = \frac{1^4}{3^4} = \frac{1}{81}$$.
Ответ: 1/81