$$\frac{1}{8} \cdot (\frac{1}{2})^{-4} = \frac{1}{2^3} \cdot (\frac{1}{2})^{-4} = (\frac{1}{2})^3 \cdot (\frac{1}{2})^{-4} = (\frac{1}{2})^{3-4} = (\frac{1}{2})^{-1} = 2$$.
Ответ: 2