1. Вычислите: a) (\(-\frac{1}{3}\))^-3 \(\cdot\) (\(-3\))⁰; б) \(\frac{2^{-3} \cdot 4^{2}}\){\(-\text{8}\)^{-2}}; в) (\(\text{5}\frac{5}{7}\))^-1 + (\(\text{5}\frac{2}{3}\))^-2 \(\cdot\) ((\(-2,5\))⁰ + (\(-1\))^-1).

1. Вычисление выражений:

1. 
   а) \(\( \left(-\frac{1}{3}\right)^{-3} \cdot \left(-3\right)^{0} \)\)
   
   \( = \left(-3\right)^{3} \cdot 1 = -27 \cdot 1 = -27 \)
   


2. 
   б) \(\( \frac{2^{-3} \cdot 4^{2}}{\left(-8\right)^{-2}} \)\)
   
   \( = \frac{\frac{1}{2^{3}} \cdot 16}{\frac{1}{\left(-8\right)^{2}}} = \frac{\frac{16}{8}}{\frac{1}{64}} = \frac{2}{1/64} = 2 \cdot 64 = 128 \)
   


3. 
   в) \(\( \left(5\frac{5}{7}\right)^{-1} + \left(5\frac{2}{3}\right)^{-2} \cdot \left(\\left(-2,5\right)^{0} + \left(-1\right)^{-1}\right) \)\)
   
   \( = \left(\frac{35+5}{7}\right)^{-1} + \left(\frac{15+2}{3}\right)^{-2} \cdot \left(1 + \left(-1\right)\right) \)
   
   \( = \left(\frac{40}{7}\right)^{-1} + \left(\frac{17}{3}\right)^{-2} \cdot \left(1 - 1\right) \)
   
   \( = \frac{7}{40} + \frac{9}{289} \cdot 0 \)
   
   \( = \frac{7}{40} \)
   

Ответ: а) -27; б) 128; в) \(\frac{7}{40}\).