1. Вычислите: a) \(\left(-\frac{1}{3}\right)^{-3}\) \(\cdot\) \((-3)^0\); б) \(\frac{2^{-3} \cdot 4^2}{(-8)^{-2}}\); в) \(\left(\left(\frac{3}{7}\right)^{-1} + \left(\frac{2}{3}\right)^{-2}\right)\) \(\cdot\) \(((-2,5)^0 + (-1)^{-1}).\)

1. Вычисление:

1. a) \( \left(-\frac{1}{3}\right)^{-3} \cdot (-3)^0 = (-3)^3 \cdot 1 = -27 \cdot 1 = -27 \)
2. б) \( \frac{2^{-3} \cdot 4^2}{(-8)^{-2}} = \frac{\frac{1}{2^3} \cdot 16}{\frac{1}{(-8)^2}} = \frac{\frac{1}{8} \cdot 16}{\frac{1}{64}} = \frac{2}{\frac{1}{64}} = 2 \cdot 64 = 128 \)
3. в) \( \left(\left(\frac{3}{7}\right)^{-1} + \left(\frac{2}{3}\right)^{-2}\right) \cdot ((-2,5)^0 + (-1)^{-1}) = \left(\frac{7}{3} + \left(\frac{3}{2}\right)^2\right) \cdot (1 + (-1)) = \left(\frac{7}{3} + \frac{9}{4}\right) \cdot (1 - 1) = \left(\frac{28 + 27}{12}\right) \cdot 0 = \frac{55}{12} \cdot 0 = 0 \)

Ответ: а) -27; б) 128; в) 0.