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МатематикаВопрос:
10) 2\(\frac{1}{9}\) \(\cdot\) 5\(\frac{1}{4}\) =
Ответ:
Решение:
Преобразуем смешанные числа в неправильные дроби:
- \(2\frac{1}{9} = \frac{2 \cdot 9 + 1}{9} = \frac{19}{9}\)
- \(5\frac{1}{4} = \frac{5 \cdot 4 + 1}{4} = \frac{21}{4}\)
Перемножим дроби:
\[ \frac{19}{9} \cdot \frac{21}{4} = \frac{19 \cdot 21}{9 \cdot 4} = \frac{19 \cdot 7}{3 \cdot 4} = \frac{133}{12} = 11\frac{1}{12} \]
Ответ: \(11\frac{1}{12}\)
Похожие
- 1) 1\(\frac{1}{2}\) \(\cdot\) 1\(\frac{1}{3}\) =
- 2) 1\(\frac{1}{5}\) \(\cdot\) 1\(\frac{1}{2}\) =
- 3) 1\(\frac{2}{3}\) \(\cdot\) 1\(\frac{1}{5}\) =
- 4) 1\(\frac{2}{7}\) \(\cdot\) 1\(\frac{3}{4}\) =
- 5) 1\(\frac{4}{5}\) \(\cdot\) 1\(\frac{1}{3}\) =
- 6) 2\(\frac{2}{3}\) \(\cdot\) 1\(\frac{6}{7}\) =
- 7) 2\(\frac{1}{7}\) \(\cdot\) 2\(\frac{4}{5}\) =
- 8) 1\(\frac{2}{9}\) \(\cdot\) 3\(\frac{3}{4}\) =
- 9) 5\(\frac{2}{7}\) \(\cdot\) 4\(\frac{2}{3}\) =
- 11) 1\(\frac{1}{19}\) \(\cdot\) \(\frac{9}{10}\) =
- 12) 3\(\frac{2}{5}\) \(\cdot\) \(\frac{1}{34}\) =
- 13) 2\(\frac{3}{4}\) \(\cdot\) \(\frac{3}{77}\) =
- 14) 3\(\frac{2}{7}\) \(\cdot\) \(\frac{3}{46}\) =
- 15) 5\(\frac{1}{11}\) \(\cdot\) 2\(\frac{1}{16}\) =
- 16) 2\(\frac{4}{25}\) \(\cdot\) 2\(\frac{8}{21}\) =
- 17) 3\(\frac{4}{9}\) \(\cdot\) 1\(\frac{19}{62}\) =
- 18) 1\(\frac{6}{49}\) \(\cdot\) 1\(\frac{23}{33}\) =
- 19) 4\(\frac{4}{15}\) \(\cdot\) 3\(\frac{3}{16}\) =
- 20) 6\(\frac{3}{4}\) \(\cdot\) 2\(\frac{1}{18}\) =
