101. Исключить иррациональность из знаменателя дроби: 1) \(\frac{2\sqrt3}{\sqrt7}\); 2) \(\frac{4\sqrt5}{\sqrt6}\); 3) \(\frac{\sqrt7+\sqrt5}{\sqrt7-\sqrt5}\); 4) \(\frac{\sqrt{11}+\sqrt3}{\sqrt3-\sqrt{11}}\).

1. \(\frac{2\sqrt3}{\sqrt7}=\frac{2\sqrt{21}}7\).
2. \(\frac{4\sqrt5}{\sqrt6}=\frac{4\sqrt{30}}6=\frac{2\sqrt{30}}3\).
3. \(\frac{\sqrt7+\sqrt5}{\sqrt7-\sqrt5}\cdot\frac{\sqrt7+\sqrt5}{\sqrt7+\sqrt5}=\frac{12+2\sqrt{35}}2=6+\sqrt{35}\).
4. \(\frac{\sqrt{11}+\sqrt3}{\sqrt3-\sqrt{11}}\cdot\frac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}}=\frac{14+2\sqrt{33}}{-8}=-\frac{7+\sqrt{33}}4\).

Ответ: 1) \(\frac{2\sqrt{21}}7\); 2) \(\frac{2\sqrt{30}}3\); 3) \(6+\sqrt{35}\); 4) \(-\frac{7+\sqrt{33}}4\).