Ответ:
ОДЗ: \(x\ne 0,7\).
\[-\frac{36}{x-7}+\frac{1}{x}=\frac{-36x+(x-7)}{x(x-7)}=\frac{-35x-7}{x(x-7)}.\]
Ответ: \(-\frac{7(5x+1)}{x(x-7)}\), \(x\ne0,7\).
ОДЗ: \(x\ne 0,7\).
\[-\frac{36}{x-7}+\frac{1}{x}=\frac{-36x+(x-7)}{x(x-7)}=\frac{-35x-7}{x(x-7)}.\]
Ответ: \(-\frac{7(5x+1)}{x(x-7)}\), \(x\ne0,7\).