Ответ:

а)

\[\frac{11}{15}\left(4\frac12-3\frac25:\frac{17}{20}\right)+1\frac{11}{20}\]

\[=\frac{11}{15}\left(\frac92-\frac{17}{5}\cdot\frac{20}{17}\right)+\frac{31}{20}\]

\[=\frac{11}{15}\left(\frac92-4\right)+\frac{31}{20}=\frac{11}{30}+\frac{31}{20}=\frac{23}{12}.\]

б)

\[5\frac47:1\frac5{21}-\left(5\frac2{15}\cdot\frac3{22}+1\frac{14}{15}\right)\]

\[=\frac{39}{7}:\frac{26}{21}-\left(\frac{77}{15}\cdot\frac3{22}+\frac{29}{15}\right)\]

\[=\frac92-\left(\frac7{10}+\frac{29}{15}\right)=\frac92-\frac{79}{30}=\frac{28}{15}.\]

в)

\[7\frac23+4\frac16\left(6\frac27-3\frac57\right)\]

\[=\frac{23}{3}+\frac{25}{6}\left(\frac{44}{7}-\frac{26}{7}\right)=\frac{23}{3}+\frac{25}{6}\cdot\frac{18}{7}\]

\[=\frac{23}{3}+\frac{75}{7}=\frac{386}{21}=18\frac8{21}.\]

г)

\[4\frac27:1\frac5{21}+\left(4\frac3{13}\cdot\frac{14}{15}-3\frac13\right)\]

\[=\frac{30}{7}:\frac{26}{21}+\left(\frac{55}{13}\cdot\frac{14}{15}-\frac{10}{3}\right)\]

\[=\frac{45}{13}+\left(\frac{154}{39}-\frac{130}{39}\right)=\frac{45}{13}+\frac8{13}=\frac{53}{13}=4\frac1{13}.\]

Ответ: а) \(\frac{23}{12}\); б) \(\frac{28}{15}\); в) \(18\frac8{21}\); г) \(4\frac1{13}\).