Ответ:
1) \(\frac{21(m^3)^6+3(m^3)^{19}}{(4m^{15})^2}=\frac{21m^{18}+3m^{57}}{16m^{30}}=\frac{3(7m^{18}+m^{57})}{16m^{30}}\), \(m\ne0\).
2) При \(a=\frac45\):
\((1-a^2)^{-\frac12}=\left(1-\frac{16}{25}\right)^{-\frac12}=\left(\frac9{25}\right)^{-\frac12}=\frac53\).
3) При \(m=\frac{16}{25}\):
\((2+m^{\frac12})^{-1}=\left(2+\sqrt{\frac{16}{25}}\right)^{-1}=\left(2+\frac45\right)^{-1}=\left(\frac{14}{5}\right)^{-1}=\frac5{14}\).
Ответ: 1) \(\frac{3(7m^{18}+m^{57})}{16m^{30}}\); 2) \(\frac53\); 3) \(\frac5{14}\).
