Решение:
\[ \frac{10}{21} : \frac{15}{28} = \frac{10}{21} \cdot \frac{28}{15} \]
\[ \frac{10}{21} \cdot \frac{28}{15} = \frac{2 \cdot 5}{3 \cdot 7} \cdot \frac{4 \cdot 7}{3 \cdot 5} = \frac{2 \cdot 4}{3 \cdot 3} = \frac{8}{9} \]
\[ \frac{25}{27} - \frac{8}{9} \]
\[ \frac{25}{27} - \frac{8 \cdot 3}{9 \cdot 3} = \frac{25}{27} - \frac{24}{27} = \frac{25 - 24}{27} = \frac{1}{27} \]
Ответ: \(\frac{1}{27}\)