Ответ:

Решение:

  1. \( \left(\frac{x^8}{y^5}\right)^5 = \frac{(x^8)^5}{(y^5)^5} = \frac{x^{8 \cdot 5}}{y^{5 \cdot 5}} = \frac{x^{40}}{y^{25}} \)
  2. \( \left(-\frac{6b^3}{7c}\right)^2 = \left(-\frac{6b^3}{7c}\right) \cdot \left(-\frac{6b^3}{7c}\right) = \frac{(-6b^3)^2}{(7c)^2} = \frac{36b^6}{49c^2} \)
  3. \( \left(-\frac{4m^2n^4}{9p^6k^7}\right)^3 = \left(-\frac{4m^2n^4}{9p^6k^7}\right) \cdot \left(-\frac{4m^2n^4}{9p^6k^7}\right) \cdot \left(-\frac{4m^2n^4}{9p^6k^7}\right) = -\frac{(4m^2n^4)^3}{(9p^6k^7)^3} = -\frac{4^3 m^{2 \cdot 3} n^{4 \cdot 3}}{9^3 p^{6 \cdot 3} k^{7 \cdot 3}} = -\frac{64 m^6 n^{12}}{729 p^{18} k^{21}} \)

Ответ: 1) \(\frac{x^{40}}{y^{25}}\); 2) \(\frac{36b^6}{49c^2}\); 3) \(-\frac{64 m^6 n^{12}}{729 p^{18} k^{21}}\).