Вопрос:

5. Решите уравнение: 1) 1,8-3b=-7-2b; 2) 2,2-5c=5c+1; 3) 3m+2=1\(\frac{3}{5}\)m-0,8; 4) 1\(\frac{1}{7}\)x-2 = -0,5x-\(\frac{3}{7}\); 5) \(\frac{x+3}{2}\) = \(\frac{3x-2}{7}\); 6) 6,6-3(x+1)=7-x; 7) 2,8-z=8(z+2,8); 8) \(\frac{5}{6}\)\(\frac{1}{2}x-\frac{2}{3}\)=3x-2\(\frac{1}{4}\); 9) \(\frac{x-3}{2}\)+\(\frac{2x-4}{3}\)=-1.

Ответ:

Решение:

  1. \( 1,8 - 3b = -7 - 2b \)
    \( -3b + 2b = -7 - 1,8 \)
    \( -b = -8,8 \)
    \( b = 8,8 \)
  2. \( 2,2 - 5c = 5c + 1 \)
    \( -5c - 5c = 1 - 2,2 \)
    \( -10c = -1,2 \)
    \( c = \frac{-1,2}{-10} = 0,12 \)
  3. \( 3m + 2 = 1\frac{3}{5}m - 0,8 \)
    \( 3m + 2 = 1,6m - 0,8 \)
    \( 3m - 1,6m = -0,8 - 2 \)
    \( 1,4m = -2,8 \)
    \( m = \frac{-2,8}{1,4} = -2 \)
  4. \( 1\frac{1}{7}x - 2 = -0,5x - \frac{3}{7} \)
    \( \frac{8}{7}x - 2 = -0,5x - \frac{3}{7} \)
    \( \frac{8}{7}x + 0,5x = 2 - \frac{3}{7} \)
    \( \frac{8}{7}x + \frac{1}{2}x = \frac{14}{7} - \frac{3}{7} \)
    \( \frac{16x + 7x}{14} = \frac{11}{7} \)
    \( \frac{23x}{14} = \frac{11}{7} \)
    \( 23x = \frac{11}{7} \cdot 14 \)
    \( 23x = 22 \)
    \( x = \frac{22}{23} \)
  5. \( \frac{x+3}{2} = \frac{3x-2}{7} \)
    \( 7(x+3) = 2(3x-2) \)
    \( 7x + 21 = 6x - 4 \)
    \( 7x - 6x = -4 - 21 \)
    \( x = -25 \)
  6. \( 6,6 - 3(x+1) = 7 - x \)
    \( 6,6 - 3x - 3 = 7 - x \)
    \( 3,6 - 3x = 7 - x \)
    \( -3x + x = 7 - 3,6 \)
    \( -2x = 3,4 \)
    \( x = \frac{3,4}{-2} = -1,7 \)
  7. \( 2,8 - z = 8(z + 2,8) \)
    \( 2,8 - z = 8z + 22,4 \)
    \( -z - 8z = 22,4 - 2,8 \)
    \( -9z = 19,6 \)
    \( z = \frac{19,6}{-9} = -\frac{196}{90} = -\frac{98}{45} \)
  8. \( \frac{5}{6}(\frac{1}{2}x - \frac{2}{3}) = 3x - 2\frac{1}{4} \)
    \( \frac{5}{12}x - \frac{10}{18} = 3x - \frac{9}{4} \)
    \( \frac{5}{12}x - \frac{5}{9} = 3x - \frac{9}{4} \)
    \( \frac{5}{12}x - 3x = \frac{5}{9} - \frac{9}{4} \)
    \( \frac{5x - 36x}{12} = \frac{20 - 81}{36} \)
    \( -\frac{31x}{12} = -\frac{61}{36} \)
    \( x = \frac{61}{36} \cdot \frac{12}{31} = \frac{61}{3 \cdot 31} = \frac{61}{93} \)
  9. \( \frac{x-3}{2} + \frac{2x-4}{3} = -1 \)
    \( \frac{3(x-3) + 2(2x-4)}{6} = -1 \)
    \( 3x - 9 + 4x - 8 = -6 \)
    \( 7x - 17 = -6 \)
    \( 7x = -6 + 17 \)
    \( 7x = 11 \)
    \( x = \frac{11}{7} \)

Ответ: 1) \( b = 8,8 \); 2) \( c = 0,12 \); 3) \( m = -2 \); 4) \( x = \frac{22}{23} \); 5) \( x = -25 \); 6) \( x = -1,7 \); 7) \( z = -\frac{98}{45} \); 8) \( x = \frac{61}{93} \); 9) \( x = \frac{11}{7} \).

Подать жалобу Правообладателю

Похожие