Ответ:\(a^{1/3}\cdot a^{1/2}=a^{5/6}\);\(b^{1/2}\cdot b^{1/3}\cdot b^{1/6}=b\);\(b^{1/3}:b^{1/6}=b^{1/6}\);\(a^{4/3}:a^{1/3}=a\);\(x^{1.7+2.8-2.5}=x^2\);\(y^{-3.8}:y^{-2.3}\cdot y^{1/3}=y^{-3.8+2.3+1/3}=y^{-7/6}\).