Ответ:
а) \(\frac{x+y}{x}+\frac{x-y}{x}+7=2+7=9\).
б) \(\frac{x+3y}{6}-\frac{x+3y}{6}+3y=3y\).
в) \(\frac{x^3-1}{x-1}+\frac{1-x^2}{x+1}=x^2+x+1-(x-1)=x^2+2\).
г) \(\frac{(x+1)^3-1}{x}+\frac{1-(x+1)^2}{x+2}=x^2+3x+3-x=x^2+2x+3\).
а) \(\frac{x+y}{x}+\frac{x-y}{x}+7=2+7=9\).
б) \(\frac{x+3y}{6}-\frac{x+3y}{6}+3y=3y\).
в) \(\frac{x^3-1}{x-1}+\frac{1-x^2}{x+1}=x^2+x+1-(x-1)=x^2+2\).
г) \(\frac{(x+1)^3-1}{x}+\frac{1-(x+1)^2}{x+2}=x^2+3x+3-x=x^2+2x+3\).