Ответ:
\(64=2^6\), \(32=2^5\): \(64^{-1}\cdot32^2=2^{-6}\cdot2^{10}=2^4=16\).
\((6^3)^2:36^5=6^6:(6^2)^5=6^6:6^{10}=6^{-4}=\frac1{1296}\).
\(4=2^2\), \(8=2^3\): \(\frac{4^{-3}\cdot2^5}{8^{-4}}=\frac{2^{-6}\cdot2^5}{2^{-12}}=2^{-1-(-12)}=2^{11}=2048\).
\(27=3^3\): \(\frac{(3^{-3})^3\cdot3^7}{27^2}=\frac{3^{-9}\cdot3^7}{3^6}=3^{-8}=\frac1{6561}\).
Жауап: 1) 16; 2) \(\frac1{1296}\); 3) 2048; 4) \(\frac1{6561}\).
