7) $(4\frac{1}{5}:x+1\frac{1}{3}):2\frac{4}{35}-\frac{4}{5}=1\frac{8}{15}$;

Question

Вопрос: $Фото задания: 7) $(4\frac{1}{5}:x+1\frac{1}{3}):2\frac{4}{35}-\frac{4}{5}=1\frac{8}{15}$;$ Фото задания

Accepted Answer

Преобразуем смешанные числа: $4\frac{1}{5}=\frac{21}{5}$, $1\frac{1}{3}=\frac{4}{3}$, $2\frac{4}{35}=\frac{74}{35}$, $1\frac{8}{15}=\frac{23}{15}$.

Получаем $\left(\frac{21}{5}:x+\frac{4}{3}\right):\frac{74}{35}-\frac{4}{5}=\frac{23}{15}$.

$\left(\frac{21}{5}:x+\frac{4}{3}\right):\frac{74}{35}=\frac{23}{15}+\frac{4}{5}=\frac{11}{15}$.

$\frac{21}{5}:x+\frac{4}{3}=\frac{11}{15}\cdot\frac{74}{35}=\frac{814}{525}$.

$\frac{21}{5}:x=\frac{814}{525}-\frac{4}{3}=\frac{114}{175}$.

$x=\frac{21}{5}:\frac{114}{175}=\frac{245}{38}$.

Ответ: $x=\frac{245}{38}$.

7) \((4\frac{1}{5}:x+1\frac{1}{3}):2\frac{4}{35}-\frac{4}{5}=1\frac{8}{15}\);