Ответ:\(2^{1-2\sqrt2}\cdot(2^2)^{\sqrt2}=2\).\(3^{2-\sqrt3}\cdot(3^3)^{\sqrt3}=3^{2+2\sqrt3}\).\(3^{2+2\sqrt3+1-\sqrt3-2-\sqrt3}=3\).\(2^{6+2\sqrt2+1-\sqrt2-4-\sqrt2}=2^3=8\).