B) (3√2 - 2√3)(2√3 + 3√2);

в) $$(3\sqrt{2} - 2\sqrt{3})(2\sqrt{3} + 3\sqrt{2}) = (3\sqrt{2} - 2\sqrt{3})(3\sqrt{2} + 2\sqrt{3}) = (3\sqrt{2})^2 - (2\sqrt{3})^2 = 9 \cdot 2 - 4 \cdot 3 = 18 - 12 = 6$$.

Ответ: 6