B) arccos (-\(\frac{\sqrt{3}}{2}\)) + arcsin (-\(\frac{\sqrt{3}}{2}\));

arccos(-\(\frac{\sqrt{3}}{2}\)) = \(\frac{5\pi}{6}\), так как cos \(\frac{5\pi}{6}\) = -\(\frac{\sqrt{3}}{2}\)

arcsin(-\(\frac{\sqrt{3}}{2}\)) = -\(\frac{\pi}{3}\), так как sin(-\(\frac{\pi}{3}\)) = -\(\frac{\sqrt{3}}{2}\)

arccos(-\(\frac{\sqrt{3}}{2}\)) + arcsin (-\(\frac{\sqrt{3}}{2}\)) = \(\frac{5\pi}{6}\) + (-\(\frac{\pi}{3}\)) = \(\frac{5\pi - 2\pi}{6}\) = \(\frac{3\pi}{6}\) = \(\frac{\pi}{2}\)

Ответ: \(\frac{\pi}{2}\)