r) arccos \(\frac{\sqrt{2}}{2}\) - arcsin \(\frac{\sqrt{3}}{2}\).

arccos \(\frac{\sqrt{2}}{2}\) = \(\frac{\pi}{4}\), так как cos \(\frac{\pi}{4}\) = \(\frac{\sqrt{2}}{2}\)

arcsin \(\frac{\sqrt{3}}{2}\) = \(\frac{\pi}{3}\), так как sin \(\frac{\pi}{3}\) = \(\frac{\sqrt{3}}{2}\)

arccos \(\frac{\sqrt{2}}{2}\) - arcsin \(\frac{\sqrt{3}}{2}\) = \(\frac{\pi}{4}\) - \(\frac{\pi}{3}\) = \(\frac{3\pi - 4\pi}{12}\) = -\(\frac{\pi}{12}\)

Ответ: -\(\frac{\pi}{12}\)