г) arcsin (-1) + arccos \(\frac{\sqrt{3}}{2}\).

arcsin (-1) = -\(\frac{\pi}{2}\), так как sin(-\(\frac{\pi}{2}\)) = -1

arccos \(\frac{\sqrt{3}}{2}\) = \(\frac{\pi}{6}\), так как cos \(\frac{\pi}{6}\) = \(\frac{\sqrt{3}}{2}\)

arcsin (-1) + arccos \(\frac{\sqrt{3}}{2}\) = -\(\frac{\pi}{2}\) + \(\frac{\pi}{6}\) = \(\frac{-3\pi + \pi}{6}\) = \(\frac{-2\pi}{6}\) = -\(\frac{\pi}{3}\)

Ответ: -\(\frac{\pi}{3}\)