arcsin \(\frac{\sqrt{3}}{2}\) = \(\frac{\pi}{3}\), так как sin \(\frac{\pi}{3}\) = \(\frac{\sqrt{3}}{2}\)
arccos \(\frac{\sqrt{3}}{2}\) = \(\frac{\pi}{6}\), так как cos \(\frac{\pi}{6}\) = \(\frac{\sqrt{3}}{2}\)
arcsin \(\frac{\sqrt{3}}{2}\) + arccos \(\frac{\sqrt{3}}{2}\) = \(\frac{\pi}{3}\) + \(\frac{\pi}{6}\) = \(\frac{2\pi + \pi}{6}\) = \(\frac{3\pi}{6}\) = \(\frac{\pi}{2}\)
Ответ: \(\frac{\pi}{2}\)