б) (x² - 3)(x + 2) + (x² + 3)(x - 2) = 4;

б) $$ (x^2 - 3)(x + 2) + (x^2 + 3)(x - 2) = 4 $$

Раскроем скобки:

$$ x^3 + 2x^2 - 3x - 6 + x^3 - 2x^2 + 3x - 6 = 4 $$

$$ 2x^3 - 12 = 4 $$

$$ 2x^3 = 16 $$

$$ x^3 = 8 $$

$$ x = 2 $$

Ответ: $$ x = 2 $$