в) (x – 4)(x + 3) + (x – 2)(x + 3) = 0;

в) $$ (x - 4)(x + 3) + (x - 2)(x + 3) = 0 $$

Раскроем скобки:

$$ x^2 + 3x - 4x - 12 + x^2 + 3x - 2x - 6 = 0 $$

$$ 2x^2 + 0x - 18 = 0 $$

$$ 2x^2 - 18 = 0 $$

$$ 2x^2 = 18 $$

$$ x^2 = 9 $$

$$ x_1 = 3, x_2 = -3 $$

Ответ: $$ x_1 = 3, x_2 = -3 $$