Ответ:
Решение:
- \( x^2 - 25 = 0 \)
\( x^2 = 25 \)
\( x = \pm \sqrt{25} \)
\( x = \pm 5 \) - \( (x+4)^2 = 0 \)
\( x+4 = 0 \)
\( x = -4 \) - \( 4x^2 - 9 = 0 \)
\( 4x^2 = 9 \)
\( x^2 = \frac{9}{4} \)
\( x = \pm \sqrt{\frac{9}{4}} \)
\( x = \pm \frac{3}{2} \) - \( x^3 - 8 = 0 \)
\( x^3 = 8 \)
\( x = \sqrt[3]{8} \)
\( x = 2 \) - \( (x-3)^2 - x^2 = 0 \)
Используем формулу разности квадратов \( a^2 - b^2 = (a-b)(a+b) \), где \( a = x-3 \) и \( b = x \).
\( ((x-3) - x)((x-3) + x) = 0 \)
\( (-3)(2x - 3) = 0 \)
\( 2x - 3 = 0 \)
\( 2x = 3 \)
\( x = \frac{3}{2} \)
Ответ: 1. \( x = \pm 5 \); 2. \( x = -4 \); 3. \( x = \pm \frac{3}{2} \); 4. \( x = 2 \); 5. \( x = \frac{3}{2} \).
