e) \(\frac{2a^2}{a^2-4a+4} - \frac{a^2+4}{a^2-4a+4} = \frac{2a^2-(a^2+4)}{a^2-4a+4} = \frac{2a^2-a^2-4}{a^2-4a+4} = \frac{a^2-4}{(a-2)^2} = \frac{(a-2)(a+2)}{(a-2)^2} = \frac{a+2}{a-2}\)
Ответ: \(\frac{a+2}{a-2}\)