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Вопрос:
log 2 1/(2√2)
Ответ:
log₂(1/(2√2)) = log₂(2⁻¹ \cdot 2⁻¹/₂) = log₂(2⁻³/₂) = -3/2
Похожие
- log 2 2
- log 2 4
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- log 3 √3
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- log 5 1
- log 5 5
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- log 5 (1/5)
- log 5 (1/25)
- log 5 (1/125)
- log 5 (1/625)
- log 5 √5
- log 5 (1/√5)
- log 8 2
- log 9
- log 27
- log 0.5 4
- log 0.2 125
- log 5 0.2
- log 5 0.04
- lg 1
- lg 10
- lg 100
- lg 1000
- lg 0.001
- lg √10
- lg 8 + lg 125
- lg 4 + lg 25
- lg 400 - lg 4
- lg 80 - lg 8
- lg 13 - lg 130
- lg 5 - lg 0.5
- log₄7 - log₄(7/16)
- log₄32 + log₄2
- log₃8 - log₃(8/9)
- log₅7 - log₅(7/25)
- log₀.₃9 - 2log₀.₃10
- log₂11 - log₂4
- log 16 / log 4
- log₂25 / og₂5
- lg 4 / lg 2
- log₃64 / log₃4
- log 100 / log 10
- log 27 / log 3
- 3 log 7
- 5 log 3
- π log 5,2
- 10 1-lg 2
- 1+log₂2
- 3 2-log 18
- 1.6 log 2
- 3.8 log 11
- (7/7)^3
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- ln e
- ln e²
- ln e³
- ln e⁴
- ln e⁵
- ln √e
- log₂x = -1
- log₂x = 0
- log₂x = 1
- log₂x = 2
- log₂x = 3
- log₂x = 4
- log₃x = -2
- log₃x = -1
- log₃x = 0
- log₃x = 1
- log₃x = 2
- log₃x = 3
- log₄x = -3
- log₄x = -2
- log₄x = -1
- log₄x = 0
- log₄x = 1
- log₄x = 2
- log₅x = -4
- log₅x = -3
- log₅x = -2
- log₅x = -1
- log₅x = 0
- log₅x = 1
- lg x = -3
- lg x = -2
- lg x = -1
- lg x = 0
- lg x = 1
- lg x = 2
- ln x = -2
- ln x = -1
- ln x = 0
- ln x = 1
- ln x = 3
- ln x = 2
- log₁/₂ x = -3
- log√₃ x = 0
- log x = 1
- log x = 2
- log₃ x = -1/2
- log₂ x = -1/2
- log₃ x = -1/2
- log₄ x = 1/2
- log₅ x = -1/2
- log₂₅ x = -1/2
- log₁₀ x = -1/2
- logx 81 = 4
- logx 1/16 = -2
- logx (1/4) = -2
- logx 27 = 3
- logx 5 = 1
- logx 16 = 4
