5419 Найдите сумму \(\frac{e}{10} + \frac{e}{25}\) при с = 1; c=3; c=7; c – 9.

1. Когда \(c = 1\): \[\frac{1}{10} + \frac{1}{25} = \frac{5}{50} + \frac{2}{50} = \frac{7}{50}\]
2. Когда \(c = 3\): \[\frac{3}{10} + \frac{3}{25} = \frac{15}{50} + \frac{6}{50} = \frac{21}{50}\]
3. Когда \(c = 7\): \[\frac{7}{10} + \frac{7}{25} = \frac{35}{50} + \frac{14}{50} = \frac{49}{50}\]
4. Когда \(c = 9\): \[\frac{9}{10} + \frac{9}{25} = \frac{45}{50} + \frac{18}{50} = \frac{63}{50} = 1\frac{13}{50}\]

Ответ: \(\frac{7}{50}\), \(\frac{21}{50}\), \(\frac{49}{50}\), \(1\frac{13}{50}\)