а) \(3^{-2} + \left(\frac{6}{5}\right)^{-1} = \frac{1}{3^2} + \frac{5}{6} = \frac{1}{9} + \frac{5}{6} = \frac{2}{18} + \frac{15}{18} = \frac{17}{18}\)
б) \(\frac{7^{-4} \cdot 7^{-9}}{7^{-14}} = \frac{7^{-4-9}}{7^{-14}} = \frac{7^{-13}}{7^{-14}} = 7^{-13-(-14)} = 7^{-13+14} = 7^1 = 7\)