a) f(x) = 5x³-4x9
f'(x) = 15x² - 36x⁸
б) f(x) =$$\frac{4x-3}{x}$$ = 4 -$$\frac{3}{x}$$
f'(x) = $$\frac{3}{x^2}$$
в) f(x) = $$\sqrt{x(12x+5)}$$ = $$\sqrt{12x^2+5x}$$
f'(x) =$$\frac{24x+5}{2\sqrt{12x^2+5x}}$$.
Ответ: а) f'(x) = 15x² - 36x⁸; б) f'(x) = $$\frac{3}{x^2}$$; в) f'(x) =$$\frac{24x+5}{2\sqrt{12x^2+5x}}$$