$$log_{\sqrt{3}} x + log_9 x = 10$$
$$log_{3^{\frac{1}{2}}} x + log_{3^2} x = 10$$
$$\frac{1}{\frac{1}{2}} log_3 x + \frac{1}{2} log_3 x = 10$$
$$2 log_3 x + \frac{1}{2} log_3 x = 10$$
$$\frac{5}{2} log_3 x = 10$$
$$log_3 x = 4$$
$$x = 3^4 = 81$$
Ответ: 81