a) 2x(3x - 1) > 4x² + 5x + 9
$$6x^2 - 2x > 4x^2 + 5x + 9$$
$$2x^2 - 7x - 9 > 0$$
$$D = 49 - 4 * 2 * (-9) = 49 + 72 = 121$$
$$x_1 = \frac{7 + 11}{4} = \frac{18}{4} = \frac{9}{2}$$
$$x_2 = \frac{7 - 11}{4} = \frac{-4}{4} = -1$$
So the solution is: x < -1 or x > 9/2
б) (5x + 7) > 4x² + 21x² - 11x - 13
This inequality is incorrect. Correct: (5x + 1)(3x - 1) > (4x - 1)(x + 2).
Ответ: a) x < -1 or x > 9/2, б) This inequality is incorrect. Correct: (5x + 1)(3x - 1) > (4x - 1)(x + 2).