в) 4x ≤ -x²; г) x² > 1 9; д) 5х² > 2x; e) -0,3x < 0,6x2.

в) 4x ≤ -x² $$x^2 + 4x ≤ 0$$ $$x(x+4) ≤ 0$$ Solving this inequality: -4 ≤ x ≤ 0 г) $$\frac{1}{3} x^2 > \frac{1}{9}$$ $$x^2 > \frac{1}{3}$$ $$x<-\frac{1}{\sqrt{3}} or x>\frac{1}{\sqrt{3}}$$ д) 5x² > 2x $$5x^2 - 2x > 0$$ $$x(5x - 2) > 0$$ Solving this inequality: x < 0 or x > 2/5 e) -0,3x < 0,6x² $$0.6x^2 + 0.3x > 0$$ $$0.3x(2x + 1) > 0$$ $$x(2x + 1) > 0$$ Solving this inequality: x < -1/2 or x > 0 Ответ: в) $$-4 ≤ x ≤ 0$$, г) $$x<-\frac{1}{\sqrt{3}} or x>\frac{1}{\sqrt{3}}$$, д) $$x < 0 or x > 2/5$$, e) $$x < -1/2 or x > 0$$