93. Сократите дробь: r) 9-2/3 2/6-2/2

г) $$\frac{9 - 2\sqrt{3}}{3\sqrt{6} - 2\sqrt{2}} = \frac{(9 - 2\sqrt{3})(3\sqrt{6} + 2\sqrt{2})}{(3\sqrt{6} - 2\sqrt{2})(3\sqrt{6} + 2\sqrt{2})} = \frac{27\sqrt{6} + 18\sqrt{2} - 6\sqrt{18} - 4\sqrt{6}}{54 - 8} = \frac{27\sqrt{6} + 18\sqrt{2} - 6 \cdot 3\sqrt{2} - 4\sqrt{6}}{46} = \frac{23\sqrt{6}}{46} = \frac{\sqrt{6}}{2}$$

Ответ: $$\frac{\sqrt{6}}{2}$$