3) $$(\frac{a^{-\frac{14}{3}}b^{6}}{a^{\frac{2}{11}}})^{\frac{6}{11}} = (a^{-\frac{14}{3} - \frac{2}{11}}b^6)^{\frac{6}{11}} = (a^{-\frac{154 + 6}{33}}b^6)^{\frac{6}{11}} = (a^{-\frac{160}{33}}b^6)^{\frac{6}{11}} = a^{-\frac{160 \cdot 6}{33 \cdot 11}}b^{\frac{36}{11}} = a^{-\frac{320}{121}}b^{\frac{36}{11}}$$.
Ответ: $$a^{-\frac{320}{121}}b^{\frac{36}{11}}$$.