$$125x^3y^4 \cdot (-\frac{1}{5}x^2y)^3 = 125x^3y^4 \cdot (-\frac{1}{5})^3 (x^2)^3 y^3 = 125x^3y^4 \cdot (-\frac{1}{125}) x^6 y^3 = -\frac{125}{125} x^{3+6} y^{4+3} = -x^9y^7$$
Ответ: $$-x^9y^7$$