a) $$ \frac{16a^{17}b^{11}}{-8a^{14}b^9} = \frac{16}{-8} \cdot \frac{a^{17}}{a^{14}} \cdot \frac{b^{11}}{b^9} = -2 \cdot a^{17-14} \cdot b^{11-9} = -2a^3b^2 $$
Ответ: $$-2a^3b^2$$