б) $$\frac{a^2 \cdot a^{n+1}a^8}{a^{n-1}a^6} = \frac{a^{2+n+1+8}}{a^{n-1+6}} = \frac{a^{n+11}}{a^{n+5}} = a^{n+11-(n+5)} = a^{n+11-n-5} = a^6$$
Ответ: $$a^6$$