в) (1\frac{11}{14}+\frac{5}{57}):\frac{14}{3}-\frac{2}{6}:1\frac{7}{32};

в) $$(1\frac{11}{14}+\frac{5}{57}):\frac{14}{3}-\frac{2}{6}:1\frac{7}{32} = (\frac{25}{14}+\frac{5}{57}):\frac{14}{3}-\frac{1}{3}:\frac{39}{32} = (\frac{25 \cdot 57 + 5 \cdot 14}{14 \cdot 57}):\frac{14}{3}-\frac{1}{3} \cdot \frac{32}{39} = (\frac{1425 + 70}{798}):\frac{14}{3}-\frac{32}{117} = \frac{1495}{798} \cdot \frac{3}{14}-\frac{32}{117} = \frac{1495 \cdot 3}{798 \cdot 14}-\frac{32}{117} = \frac{4485}{11172}-\frac{32}{117} = \frac{5 \cdot 897}{4 \cdot 2793}-\frac{32}{117} = \frac{5 \cdot 3 \cdot 299}{4 \cdot 3 \cdot 931}-\frac{32}{117} = \frac{1495}{3724}-\frac{32}{117} = \frac{1495 \cdot 117 - 32 \cdot 3724}{435708} = \frac{174915 - 119168}{435708} = \frac{55747}{435708}$$

Ответ: $$\frac{55747}{435708}$$