Ответ:
Подставим значения \(t=3,4,5,6,7\):
\(\displaystyle\frac1{5!}-\frac1{7!}+\frac1{9!}-\frac1{11!}+\frac1{13!}=\frac1{120}-\frac1{5040}+\frac1{362880}-\frac1{39916800}+\frac1{6227020800}.\)
Ответ: \(\displaystyle\frac1{120}-\frac1{5040}+\frac1{362880}-\frac1{39916800}+\frac1{6227020800}\).
