**1) $$3\frac{1}{16} - \frac{1}{8}$$**
$$3 + \frac{1}{16} - \frac{1}{8} = 3 + \frac{1}{16} - \frac{2}{16} = 3 - \frac{1}{16} = 2\frac{16}{16} - \frac{1}{16} = 2\frac{15}{16}$$
**2) $$7\frac{9}{20} - 5\frac{17}{30}$$**
$$7 - 5 = 2$$
Приведем дроби к общему знаменателю, который равен 60.
$$\frac{9}{20} = \frac{9 \cdot 3}{20 \cdot 3} = \frac{27}{60}$$
$$\frac{17}{30} = \frac{17 \cdot 2}{30 \cdot 2} = \frac{34}{60}$$
Т.к. $$\frac{27}{60} < \frac{34}{60}$$, занимаем 1 у целой части.
$$2\frac{27}{60} = 1 + 1\frac{27}{60} = 1 + \frac{60}{60} + \frac{27}{60} = 1\frac{87}{60}$$
$$1\frac{87}{60} - \frac{34}{60} = 1\frac{53}{60}$$
**3) $$4\frac{2}{7} - 1\frac{4}{9}$$**
$$4 - 1 = 3$$
Приведем дроби к общему знаменателю, который равен 63.
$$\frac{2}{7} = \frac{2 \cdot 9}{7 \cdot 9} = \frac{18}{63}$$
$$\frac{4}{9} = \frac{4 \cdot 7}{9 \cdot 7} = \frac{28}{63}$$
Т.к. $$\frac{18}{63} < \frac{28}{63}$$, занимаем 1 у целой части.
$$3\frac{18}{63} = 2 + 1\frac{18}{63} = 2 + \frac{63}{63} + \frac{18}{63} = 2\frac{81}{63}$$
$$2\frac{81}{63} - \frac{28}{63} = 2\frac{53}{63}$$
**4) $$8\frac{5}{36} - 1\frac{43}{108}$$**
$$8 - 1 = 7$$
Приведем дроби к общему знаменателю, который равен 108.
$$\frac{5}{36} = \frac{5 \cdot 3}{36 \cdot 3} = \frac{15}{108}$$
Т.к. $$\frac{15}{108} < \frac{43}{108}$$, занимаем 1 у целой части.
$$7\frac{15}{108} = 6 + 1\frac{15}{108} = 6 + \frac{108}{108} + \frac{15}{108} = 6\frac{123}{108}$$
$$6\frac{123}{108} - \frac{43}{108} = 6\frac{80}{108} = 6\frac{20}{27}$$
**5) $$9\frac{7}{32} - 4\frac{5}{6}$$**
$$9 - 4 = 5$$
Приведем дроби к общему знаменателю, который равен 96.
$$\frac{7}{32} = \frac{7 \cdot 3}{32 \cdot 3} = \frac{21}{96}$$
$$\frac{5}{6} = \frac{5 \cdot 16}{6 \cdot 16} = \frac{80}{96}$$
Т.к. $$\frac{21}{96} < \frac{80}{96}$$, занимаем 1 у целой части.
$$5\frac{21}{96} = 4 + 1\frac{21}{96} = 4 + \frac{96}{96} + \frac{21}{96} = 4\frac{117}{96}$$
$$4\frac{117}{96} - \frac{80}{96} = 4\frac{37}{96}$$
**6) $$6\frac{7}{32} - 2\frac{11}{48}$$**
$$6 - 2 = 4$$
Приведем дроби к общему знаменателю, который равен 96.
$$\frac{7}{32} = \frac{7 \cdot 3}{32 \cdot 3} = \frac{21}{96}$$
$$\frac{11}{48} = \frac{11 \cdot 2}{48 \cdot 2} = \frac{22}{96}$$
Т.к. $$\frac{21}{96} < \frac{22}{96}$$, занимаем 1 у целой части.
$$4\frac{21}{96} = 3 + 1\frac{21}{96} = 3 + \frac{96}{96} + \frac{21}{96} = 3\frac{117}{96}$$
$$3\frac{117}{96} - \frac{22}{96} = 3\frac{95}{96}$$