ж) $$\frac{24}{11} \cdot \frac{6}{18} \cdot 4\frac{1}{8} : 1\frac{5}{6} : 1\frac{14}{22}$$

ж) Переведем смешанные числа в неправильные дроби:

$$4\frac{1}{8} = \frac{4 \cdot 8 + 1}{8} = \frac{32 + 1}{8} = \frac{33}{8}$$;

$$1\frac{5}{6} = \frac{1 \cdot 6 + 5}{6} = \frac{6 + 5}{6} = \frac{11}{6}$$;

$$1\frac{14}{22} = \frac{1 \cdot 22 + 14}{22} = \frac{22 + 14}{22} = \frac{36}{22} = \frac{18}{11}$$.

Тогда:

$$\frac{24}{11} \cdot \frac{6}{18} \cdot 4\frac{1}{8} : 1\frac{5}{6} : 1\frac{14}{22} = \frac{24}{11} \cdot \frac{6}{18} \cdot \frac{33}{8} : \frac{11}{6} : \frac{18}{11} = \frac{24}{11} \cdot \frac{6}{18} \cdot \frac{33}{8} \cdot \frac{6}{11} \cdot \frac{11}{18} = \frac{24 \cdot 6 \cdot 33 \cdot 6 \cdot 11}{11 \cdot 18 \cdot 8 \cdot 11 \cdot 18} = \frac{24 \cdot 6 \cdot 3 \cdot 6}{18 \cdot 8 \cdot 18} = \frac{24 \cdot 6 \cdot 3 \cdot 6}{6 \cdot 3 \cdot 8 \cdot 6 \cdot 3} = \frac{24}{8 \cdot 3} = \frac{24}{24} = 1$$.

Ответ: 1