а) $$\frac{2a+10}{3b-9} : \frac{4b-12}{a+5}$$
\[ \frac{2a+10}{3b-9} \cdot \frac{a+5}{4b-12} \]
\[ \frac{2(a+5)}{3(b-3)} \cdot \frac{a+5}{4(b-3)} \]
\[ \frac{2(a+5)(a+5)}{3(b-3)4(b-3)} = \frac{2(a+5)^2}{12(b-3)^2} \]
\[ \frac{(a+5)^2}{6(b-3)^2} \]
Ответ: $$\frac{(a+5)^2}{6(b-3)^2}$$