Ответ:
Решение:
\( \frac{S_{MPT}}{S_{XOY}} = K^2 \)
\( \frac{10}{S_{XOY}} = (0.5)^2 \)
\( \frac{10}{S_{XOY}} = 0.25 \)
\( S_{XOY} = \frac{10}{0.25} = 40 \).
Ответ: SXOY = 40.
\( \frac{S_{MPT}}{S_{XOY}} = K^2 \)
\( \frac{10}{S_{XOY}} = (0.5)^2 \)
\( \frac{10}{S_{XOY}} = 0.25 \)
\( S_{XOY} = \frac{10}{0.25} = 40 \).
Ответ: SXOY = 40.